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Find the Geometric Mean of 8 and 24\ \>", "Subsection", CellChangeTimes->{{3.7379757436839933`*^9, 3.73797575142819*^9}, { 3.7379757835318193`*^9, 3.737975799900832*^9}, {3.7379758412582817`*^9, 3.737975848827133*^9}},ExpressionUUID->"d856b67c-1864-4082-aae2-\ 8d4885463ebf"], Cell[CellGroupData[{ Cell[BoxData[{ RowBox[{ RowBox[{"d", "[", RowBox[{"a_", ",", "b_"}], "]"}], ":=", SqrtBox[ RowBox[{"a", "*", "b"}]]}], "\[IndentingNewLine]", RowBox[{"d", "[", RowBox[{"8", ",", "24"}], "]"}]}], "Input", CellChangeTimes->{{3.7379757179600782`*^9, 3.737975718160151*^9}, { 3.7379758555545473`*^9, 3.7379759507793503`*^9}},ExpressionUUID->"57f4c99c-8ace-4e32-afa0-\ 344f6916daa0"], Cell[BoxData[ RowBox[{"8", " ", SqrtBox["3"]}]], "Output", CellChangeTimes->{ 3.7379759520345984`*^9},ExpressionUUID->"3de0cd78-0672-4f09-a193-\ 15a7010509b4"] }, Open ]] }, Open ]], Cell["", "Subsection",ExpressionUUID->"8fbe765c-7608-4deb-a7e2-bf57c4e1a78c"] }, Closed]] }, Open ]], Cell[CellGroupData[{ Cell[TextData[{ "\n", StyleBox["Zeno\[CloseCurlyQuote]s paradox and Infinite Geometric Series", FontSize->48] }], "Subtitle", CellChangeTimes->{{3.737975997790352*^9, 3.737976025272807*^9}, 3.737976571576777*^9},ExpressionUUID->"c1d6440a-a585-45f5-ba4f-\ 7d9cf40fd79d"], Cell[CellGroupData[{ Cell[TextData[StyleBox["Calculating the Infinite Geometric Series", FontColor->RGBColor[1, 0, 1]]], "Section", CellChangeTimes->{{3.737976038681799*^9, 3.737976083317996*^9}},ExpressionUUID->"a2b4b697-ea49-4a34-a521-\ 04cc40b18c26"], Cell[CellGroupData[{ Cell["\<\ If r is -1 > r > 1, then its convergent Example 1: Find the sum to infinity to the series 1/2 + 1/4 + 1/8 ...\ \>", "Subsection", CellChangeTimes->{{3.7379761063868237`*^9, 3.7379761239327383`*^9}, { 3.737976169069538*^9, 3.737976178553363*^9}, {3.737976230793324*^9, 3.737976287586494*^9}},ExpressionUUID->"f10a8f2e-3de0-4729-953d-\ 0fa7e6c011fd"], Cell[CellGroupData[{ Cell[BoxData[{ RowBox[{ RowBox[{"K", "[", RowBox[{"a_", ",", "r_"}], "]"}], ":=", FractionBox["a", RowBox[{"1", "-", "r"}]]}], "\[IndentingNewLine]", RowBox[{"K", "[", RowBox[{ FractionBox["1", "2"], ",", FractionBox["1", "2"]}], "]"}]}], "Input", CellChangeTimes->{{3.737976086645933*^9, 3.737976100690749*^9}, { 3.737976132189475*^9, 3.737976132574522*^9}, {3.737976186711275*^9, 3.7379761993576937`*^9}, {3.737976291989601*^9, 3.737976330401556*^9}},ExpressionUUID->"73388cf3-3ecd-4075-9fd4-\ 0ba869ed8e2a"], Cell[BoxData["1"], "Output", CellChangeTimes->{{3.737976314192606*^9, 3.737976331169361*^9}},ExpressionUUID->"a28d020d-6005-4356-9e45-\ bcd708f1a090"] }, Open ]] }, Open ]], Cell[CellGroupData[{ Cell["\<\ Example 2: Express the recurring decimal 0.3*2* as the ratio of two integers\ \>", "Subsection", CellChangeTimes->{{3.73797638183*^9, 3.737976498384041*^9}},ExpressionUUID->"51fcff16-d501-487a-ae9f-\ f34c8cfcf6bc"], Cell[CellGroupData[{ Cell[BoxData[{ RowBox[{ RowBox[{"K", "[", RowBox[{"a_", ",", "r_"}], "]"}], ":=", FractionBox["a", RowBox[{"1", "-", "r"}]]}], "\[IndentingNewLine]", RowBox[{"K", "[", RowBox[{ FractionBox["32", "100"], ",", FractionBox["1", "100"]}], "]"}]}], "Input", CellChangeTimes->{{3.737976342051303*^9, 3.737976342399193*^9}, { 3.7379765044255247`*^9, 3.7379765557296343`*^9}},ExpressionUUID->"a23c4c14-1f1f-479b-a7df-\ 99fd61d3a5d5"], Cell[BoxData[ FractionBox["32", "99"]], "Output", CellChangeTimes->{{3.737976530257094*^9, 3.7379765564449673`*^9}},ExpressionUUID->"2fcd3aa7-cdac-477f-8e15-\ 8610caae74e6"] }, Open ]] }, Open ]] }, Closed]] }, Open ]], Cell[CellGroupData[{ Cell[TextData[StyleBox["\nBinomial distribution and Hypergeometric \ Distribution \[LongRightArrow] Probability", FontSize->48]], "Subtitle", CellChangeTimes->{{3.737953407693619*^9, 3.737953443572145*^9}, { 3.7379535417083693`*^9, 3.737953566533063*^9}, 3.7379731563531713`*^9},ExpressionUUID->"2a27004c-4bda-449b-b510-\ 36505e4fd01b"], Cell[CellGroupData[{ Cell[TextData[StyleBox["Binomial Distribution", FontColor->RGBColor[1, 0, 1]]], "Section", CellChangeTimes->{{3.7379534667622213`*^9, 3.7379534782792387`*^9}, { 3.737953569608287*^9, 3.7379535810039873`*^9}, {3.7820730511318913`*^9, 3.782073053580937*^9}},ExpressionUUID->"aecc5405-4ef2-44a8-abcf-\ 13ef02d2281c"], Cell[CellGroupData[{ Cell["\<\ For binomial distribution to be possible, it needs to have 1) A set number of trials 2) A set number of samples (also seen as \[OpenCurlyQuote] with replacement\ \[CloseCurlyQuote]) 3) Only two results: Success or Failure Representation of the Binomial form in Mathematica\ \>", "Subsection", CellChangeTimes->{{3.737953588011574*^9, 3.737953588341549*^9}, { 3.737955293812372*^9, 3.73795537647653*^9}, {3.7379628694227877`*^9, 3.7379628943470097`*^9}, {3.737966089998658*^9, 3.737966115708057*^9}, { 3.737971216376068*^9, 3.73797123430508*^9}},ExpressionUUID->"7f858c78-3f24-48d5-a645-\ 6abcb45594d1"], Cell[CellGroupData[{ Cell["\<\ Example 1: Suppose 10 males are selected at random. Find the probability, \ correct to four decimals \ \>", "Subsubsection", CellChangeTimes->{ 3.737963107202821*^9, {3.737963679047431*^9, 3.737963682449471*^9}},ExpressionUUID->"4cf4dd62-456d-4810-88c8-\ 4f4ecc134cf7"], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{"Probability", "[", RowBox[{ RowBox[{"x", "\[GreaterEqual]", "2"}], ",", RowBox[{"x", "\[Distributed]", RowBox[{"BinomialDistribution", "[", RowBox[{"10", ",", "0.0993"}], "]"}]}]}], "]"}]], "Input", CellChangeTimes->{{3.737953590780734*^9, 3.7379535910014277`*^9}, 3.737963139733388*^9},ExpressionUUID->"b1241c13-a32e-403c-8ff5-\ efb1565cf157"], Cell[BoxData["0.2611902062457971`"], "Output", CellChangeTimes->{ 3.7379631410784607`*^9},ExpressionUUID->"366ef63f-8e0f-49d2-85cd-\ 245c03186381"] }, Open ]] }, Open ]], Cell[CellGroupData[{ Cell["\<\ Example 2: Suppose that the probability that a person selected at random is \ left-handed is always 0.2 . If 11 people are selected at random for the \ cricket team: \ \>", "Subsubsection", CellChangeTimes->{{3.737963692043007*^9, 3.7379637519557543`*^9}, { 3.737963864667583*^9, 3.737963873556452*^9}},ExpressionUUID->"161afa52-f35f-438f-91fb-\ 6bd28172b5e6"], Cell[CellGroupData[{ Cell["\<\ a) Find the probability of selecting exactly two left-handed.\ \>", "Subsubsubsection", CellChangeTimes->{{3.73796388832302*^9, 3.737963919573493*^9}, { 3.737966021107958*^9, 3.73796602191053*^9}},ExpressionUUID->"bdecef72-3317-4066-a9fe-\ 76c0c3d6455d"], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{"Probability", "[", RowBox[{ RowBox[{"x", "\[Equal]", "2"}], ",", RowBox[{"x", "\[Distributed]", RowBox[{"BinomialDistribution", "[", RowBox[{"11", ",", "0.2"}], "]"}]}]}], "]"}]], "Input", CellChangeTimes->{{3.737965099378373*^9, 3.737965123338533*^9}},ExpressionUUID->"c2882756-0bc0-46f1-a672-\ 4cb6bd17a9ad"], Cell[BoxData["0.29527900160000004`"], "Output", CellChangeTimes->{ 3.737965124459569*^9},ExpressionUUID->"2b1d7a35-ad70-47cd-9e0c-\ 3c5560e754f7"] }, Open ]] }, Open ]], Cell[CellGroupData[{ Cell["\<\ b) Find the probability of selecting at least four left-handed.\ \>", "Subsubsubsection", CellChangeTimes->{{3.7379652708995132`*^9, 3.7379652857660007`*^9}, { 3.737965478692932*^9, 3.7379654969541187`*^9}, {3.737966017373228*^9, 3.7379660183719463`*^9}},ExpressionUUID->"1849d6f3-ecde-4bb8-8c59-\ 16733c8f4c1c"], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{"Probability", "[", RowBox[{ RowBox[{"x", "\[GreaterEqual]", "4"}], ",", RowBox[{"x", "\[Distributed]", RowBox[{"BinomialDistribution", "[", RowBox[{"11", ",", "0.2"}], "]"}]}]}], "]"}]], "Input", CellChangeTimes->{{3.7379660249989157`*^9, 3.737966064886698*^9}},ExpressionUUID->"523f479b-0546-4f3c-8545-\ b58ac6d3691e"], Cell[BoxData["0.16113920000000015`"], "Output", CellChangeTimes->{ 3.737966065662746*^9},ExpressionUUID->"b7bc236e-3bb4-43ab-bb88-\ 9ff412dd71cd"] }, Open ]] }, Open ]] }, Open ]], Cell[CellGroupData[{ Cell["\<\ Example 3: Monique is practising goaling for netball. 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3.737970583233407*^9}},ExpressionUUID->"9a06586b-9805-4db0-8d4b-\ f55b319382f7"], Cell[CellGroupData[{ Cell[TextData[StyleBox["Normal Deviation", FontColor->RGBColor[1, 0, 1]]], "Section", CellChangeTimes->{ 3.737950745246895*^9, {3.737950783782189*^9, 3.737950789671053*^9}, 3.737953469749559*^9},ExpressionUUID->"75c21fc3-7c32-4fa9-8029-\ 282be88f4ee3"], Cell[CellGroupData[{ Cell[TextData[{ "Normal distribution command format: NormalDistribution[\[Micro], \[Sigma] ]\ \n\[Micro] is the mean\n\[Sigma] is the standard deviation\n", StyleBox["Example 1: The results of a maths exam are normally distributed \ with \[Micro] = 50, and \[Sigma] =7", FontColor->RGBColor[0.5, 0, 0.5]] }], "Subsection", CellChangeTimes->{{3.737952082699656*^9, 3.737952141696162*^9}, { 3.737952249657895*^9, 3.737952273739698*^9}, {3.737952379039804*^9, 3.7379524021376143`*^9}, {3.737971767371607*^9, 3.737971881106937*^9}},ExpressionUUID->"86cbef4a-e462-4f82-aa63-\ 87e60e705179"], Cell[CellGroupData[{ Cell["\<\ a) What is the probability a student has an exam mark greater than 60.\ \>", "Subsubsection", CellChangeTimes->{ 3.7379523143961287`*^9},ExpressionUUID->"0c937a80-ffe0-4a61-ae2d-\ 2ac71be050cd"], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{ RowBox[{"Probability", "[", RowBox[{ RowBox[{"x", ">", "60"}], ",", RowBox[{"x", "\[Distributed]", RowBox[{"NormalDistribution", "[", RowBox[{"50", ",", "7"}], "]"}]}]}], "]"}], "//", "N"}]], "Input", CellChangeTimes->{{3.737952296144755*^9, 3.737952323500965*^9}}, CellLabel->"In[7]:=",ExpressionUUID->"fe9e2464-8af0-4765-90cc-834d05d4628e"], Cell[BoxData["0.07656372550983476`"], "Output", CellChangeTimes->{3.737952324872837*^9}, CellLabel->"Out[7]=",ExpressionUUID->"61cdd3da-8891-4e06-9fea-3ad3a1c47ad2"] }, Open ]] }, Open ]], Cell[CellGroupData[{ Cell["\<\ b) If 25 students are selected, what is the probability at least 10 have a \ greater score than 60.\ \>", "Subsubsection", CellChangeTimes->{ 3.737952459819214*^9},ExpressionUUID->"a19d447f-05d2-4fe1-a6d4-\ d80e92650900"], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{ RowBox[{"Probability", "[", RowBox[{ RowBox[{"x", "\[GreaterEqual]", "10"}], ",", RowBox[{"x", "\[Distributed]", RowBox[{"BinomialDistribution", "[", RowBox[{"25", ",", "0.0766"}], "]"}]}]}], "]"}], "//", "N"}]], "Input", CellChangeTimes->{{3.737952467396145*^9, 3.737952476091692*^9}}, CellLabel->"In[8]:=",ExpressionUUID->"db7823df-f9b9-42ab-8f45-49b65030336c"], Cell[BoxData["7.7390619497788`*^-6"], "Output", CellChangeTimes->{3.737952477169477*^9}, CellLabel->"Out[8]=",ExpressionUUID->"acaf1d9e-8eab-490b-b9cb-81a8f49723c7"] }, Open ]] }, Open ]], Cell[CellGroupData[{ Cell["\<\ c) The top 15% are awarded a distinction. What minimum mark guarantees a \ distinction?\ \>", "Subsubsection", CellChangeTimes->{ 3.737952490561893*^9},ExpressionUUID->"eb505847-2ae2-4f53-a67e-\ 8a47ed456bf4"], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{"Quantile", "[", RowBox[{ RowBox[{"NormalDistribution", "[", RowBox[{"50", ",", "7"}], "]"}], ",", "0.85"}], "]"}]], "Input", CellChangeTimes->{{3.737952497610569*^9, 3.73795250484175*^9}}, CellLabel->"In[9]:=",ExpressionUUID->"1dc5fff6-ed96-4c66-97f3-cb52476afbd6"], Cell[BoxData["57.255033726456524`"], "Output", CellChangeTimes->{3.737952505918744*^9}, CellLabel->"Out[9]=",ExpressionUUID->"3325c4f4-66e2-49da-87a4-d3e5013162ca"] }, Open ]], Cell["\<\ Quantile is function used to find the point on the x-axis, when the success \ probability or the space it covers is given in percentage covered by the \ graph. Key words to look for --> minimum and maximum \ \>", "Text", CellChangeTimes->{{3.737952921338146*^9, 3.737952932518478*^9}, { 3.7379533312848663`*^9, 3.737953379223424*^9}, {3.737966448814187*^9, 3.737966461784892*^9}, {3.737966492858951*^9, 3.737966529218351*^9}, { 3.737966597691884*^9, 3.737966653799399*^9}},ExpressionUUID->"40291466-e0c0-4f74-9bc1-\ 9529f8fb5936"] }, Open ]] }, Open ]] }, Closed]], Cell[CellGroupData[{ Cell[TextData[StyleBox["Standard Normal Distribution", FontColor->RGBColor[1, 0, 1]]], "Section", CellChangeTimes->{{3.737964424665765*^9, 3.737964426298418*^9}, { 3.7379644702012978`*^9, 3.737964483468678*^9}, {3.737970161740251*^9, 3.7379701682242804`*^9}, {3.7379705749638577`*^9, 3.737970577030295*^9}},ExpressionUUID->"70fe83a7-e0bd-45f9-85a7-\ 23161200852a"], Cell["\<\ Note: The Normal distribution with a constant mean of 0 and standard \ deviation of 1 is known as a standard normal distribution.\ \>", "Subsection", CellChangeTimes->{ 3.7379706072162247`*^9},ExpressionUUID->"6df0be3e-5e0f-4e4b-87d9-\ 85f051f2575a"], Cell[CellGroupData[{ Cell["\<\ A taxi company determined that on an annual basis the distance travelled per \ taxi is normally distributed with a mean of 92,000 kilometres and a standard \ deviation of 23,500 kilometres.\ \>", "Subsection", CellChangeTimes->{{3.7379701218689947`*^9, 3.7379701260410967`*^9}, { 3.73797016976*^9, 3.7379701881798*^9}, {3.737970293498212*^9, 3.737970327782881*^9}},ExpressionUUID->"20588c9b-707a-4c65-a25f-\ 9c9b8f86b75e"], Cell[CellGroupData[{ Cell["\<\ a. What is the probability, correct to four decimal places, that a taxi \ travels less than 75 000 kilometres per year?\ \>", "Subsubsection", CellChangeTimes->{ 3.7379704608758497`*^9},ExpressionUUID->"6b49a7db-2ee7-4e6e-bab7-\ 9c7aec7b319f"], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{ RowBox[{"Probability", "[", RowBox[{ RowBox[{"x", "<", "75000"}], ",", RowBox[{"x", "\[Distributed]", RowBox[{"NormalDistribution", "[", RowBox[{"92000", ",", "23500"}], "]"}]}]}], "]"}], "//", "N"}]], "Input", CellChangeTimes->{{3.737970111722909*^9, 3.737970112624995*^9}, { 3.737970478948126*^9, 3.7379705090087147`*^9}}, CellLabel->"In[23]:=",ExpressionUUID->"4022dc82-58e7-43eb-81c2-f273adea00df"], Cell[BoxData["0.23471577882277778`"], "Output", CellChangeTimes->{3.7379705130865507`*^9}, CellLabel->"Out[23]=",ExpressionUUID->"b2640796-9321-40aa-a178-b229e0705de4"] }, Open ]] }, Open ]], Cell[CellGroupData[{ Cell["\<\ b. What is the probability, correct to four decimal places, that a taxi \ travels more than 80,00 kilometers per year?\ \>", "Subsubsection", CellChangeTimes->{{3.737970671330208*^9, 3.7379707274385223`*^9}},ExpressionUUID->"ab12e1e5-ce60-4b0a-8091-\ 20c89c56aab6"], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{ RowBox[{"Probability", "[", RowBox[{ RowBox[{"x", ">", "80000"}], ",", RowBox[{"x", "\[Distributed]", RowBox[{"NormalDistribution", "[", RowBox[{"92000", ",", "23500"}], "]"}]}]}], "]"}], "//", "N"}]], "Input", CellChangeTimes->{{3.737970650262258*^9, 3.737970651130116*^9}, 3.737970737142376*^9}, CellLabel->"In[24]:=",ExpressionUUID->"a6e36c50-aba2-4843-872e-1cbac4f68851"], Cell[BoxData["0.6951978232591206`"], "Output", CellChangeTimes->{3.737970737841722*^9}, CellLabel->"Out[24]=",ExpressionUUID->"848f6fbf-2cde-4fd3-91fd-2f8580bc80be"] }, Open ]] }, Open ]], Cell[CellGroupData[{ Cell["\<\ c. What is the probability, correct to four decimal places, that a taxi \ travels between 60,00 and 100,000 kilometers per year\ \>", "Subsubsection", CellChangeTimes->{{3.7379707437969847`*^9, 3.737970800772764*^9}},ExpressionUUID->"752caf8f-db60-43ad-bbec-\ 9e9682d9c1ea"], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{ RowBox[{"Probability", "[", RowBox[{ RowBox[{"60000", "<", "x", "<", "100000"}], ",", RowBox[{"x", "\[Distributed]", RowBox[{"NormalDistribution", "[", RowBox[{"92000", ",", "23500"}], "]"}]}]}], "]"}], "//", "N"}]], "Input", CellChangeTimes->{{3.7379708033689423`*^9, 3.737970810963896*^9}}, CellLabel->"In[25]:=",ExpressionUUID->"e2fee661-80c7-4d3c-b8e5-50742bf8c882"], Cell[BoxData["0.5465859982536845`"], "Output", CellChangeTimes->{3.7379708116353083`*^9}, CellLabel->"Out[25]=",ExpressionUUID->"d718b02e-5c64-4d41-8aaa-cdf02ebc75d5"] }, Open ]] }, Open ]], Cell[CellGroupData[{ Cell["\<\ d. Find the minimum mileage that could be expected by 95% of taxis, to the \ nearest km. (Hint: Quantile function can only deal with probabilities that \ exist in the left tail of the normal distribution)\ \>", "Subsubsection", CellChangeTimes->{{3.737970836700658*^9, 3.7379709509568644`*^9}},ExpressionUUID->"d89f0a17-f2f8-4e33-9f60-\ c2dcf7f2f790"], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{ RowBox[{"Quantile", "[", RowBox[{ RowBox[{"NormalDistribution", "[", RowBox[{"92000", ",", "23500"}], "]"}], ",", "0.05"}], "]"}], "//", "N"}]], "Input", CellChangeTimes->{{3.737970955495329*^9, 3.7379709640132103`*^9}}, CellLabel->"In[26]:=",ExpressionUUID->"a1201dd2-de65-44d4-8462-a40399e95a7f"], Cell[BoxData["53345.93976664039`"], "Output", CellChangeTimes->{3.737970965054008*^9}, CellLabel->"Out[26]=",ExpressionUUID->"95471f8a-3a5b-486d-a354-1dd11bdb5225"] }, Open ]], Cell["\<\ Quantile command format is : Quantile[distribution, Percentage]\ \>", "Text", CellChangeTimes->{{3.737970980524639*^9, 3.73797102907386*^9}},ExpressionUUID->"f151956a-bb99-45ac-9dd6-\ 93a7f1f9d877"] }, 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